# Line slope calculator 3x+7y=62

**Straight line given by points A[2; 8] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.4286x+8.8571

**Canonical form of the line equation:**3x+7y-62 = 0

**Parametric form of the line equation:**

x = 7t+2

y = -3t+8 ; t ∈ R

**Slope:**m = -0.4286

**Slope angle of line: φ =**-23°11'55″ = -0.4049 rad

**X intercept:**x

_{0}= 20.6667

**Y intercept:**y

_{0}= q = 8.8571

**Distance line from the origin:**d

_{0}= 8.141

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(7; -3)

**Normal vector: n =**(3; 7)

**Midpoint of the segment AB: M =**[5.5; 6.5]

**Perpendicular Bisector equation:**7x-3y-19 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 58**

**Angle ∠ AOB = 46°54'33″ = 0.8187 rad**