# Line slope calculator 7x-3y=40

**Straight line given by points A[7; 3] and B[10; 10]**

## Calculation:

**Slope-intercept form of line:**y = 2.3333x-13.3333

**Canonical form of the line equation:**7x-3y-40 = 0

**Parametric form of the line equation:**

x = 3t+7

y = 7t+3 ; t ∈ R

**Slope:**m = 2.3333

**Slope angle of line: φ =**66°48'5″ = 1.1659 rad

**X intercept:**x

_{0}= 5.7143

**Y intercept:**y

_{0}= q = -13.3333

**Distance line from the origin:**d

_{0}= 5.2523

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(3; 7)

**Normal vector: n =**(7; -3)

**Midpoint of the segment AB: M =**[8.5; 6.5]

**Perpendicular Bisector equation:**3x+7y-71 = 0

**Vector OA = (7; 3) ; |OA| = 7.6158**

**Vector OB = (10; 10) ; |OB| = 14.1421**

**Scalar product OA .OB = 100**

**Angle ∠ AOB = 21°48'5″ = 0.3805 rad**